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Display information for equation id:math.1326.118 on revision:1326

* Page found: Der Hamiltonsche kanonische Formalismus (eq math.1326.118)

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Occurrences on the following pages:

Hash: 018d10b4c71a7bfbfac24371f1a600aa

TeX (original user input):

\delta \bar{q}({{t}_{1}})=\delta \bar{q}({{t}_{2}})=0

TeX (checked):

\delta {\bar {q}}({{t}_{1}})=\delta {\bar {q}}({{t}_{2}})=0

LaTeXML (experimentell; verwendet MathML) rendering

MathML (4.813 KB / 898 B) :

δ q ¯ ( t 1 ) = δ q ¯ ( t 2 ) = 0 𝛿 ¯ 𝑞 subscript 𝑡 1 𝛿 ¯ 𝑞 subscript 𝑡 2 0 {\displaystyle{\displaystyle\delta\bar{q}({{t}_{1}})=\delta\bar{q}({{t}_{2}})=% 0}}
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MathML (experimentell; keine Bilder) rendering

MathML (703 B / 245 B) :

δq¯(t1)=δq¯(t2)=0
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Identifiers

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  • q¯
  • t1
  • δ
  • q¯
  • t2

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