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Display information for equation id:math.1626.41 on revision:1626

* Page found: Operatoren im Hilbertraum (eq math.1626.41)

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Hash: cc3ca84b6214038003aff34a6e364961

TeX (original user input): 

\left( {{\Psi }_{1}},\hat{F}{{\Psi }_{2}} \right)=\left( \hat{F}{{\Psi }_{1}},{{\Psi }_{2}} \right)\quad \forall {{\Psi }_{1}},{{\Psi }_{2}}\in H

TeX (checked): 

\left({{\Psi }_{1}},{\hat {F}}{{\Psi }_{2}}\right)=\left({\hat {F}}{{\Psi }_{1}},{{\Psi }_{2}}\right)\quad \forall {{\Psi }_{1}},{{\Psi }_{2}}\in H

LaTeXML (experimentell; verwendet MathML) rendering

MathML (8.443 KB / 1.385 KB) :

( Ψ 1 , F ^ ⁢ Ψ 2 ) = ( F ^ ⁢ Ψ 1 , Ψ 2 )   ∀ Ψ 1 , Ψ 2 ∈ H formulae-sequence subscript Ψ 1 ^ 𝐹 subscript Ψ 2 ^ 𝐹 subscript Ψ 1 subscript Ψ 2 for-all subscript Ψ 1 subscript Ψ 2 𝐻 {\displaystyle{\displaystyle\left({{\Psi}_{1}},\hat{F}{{\Psi}_{2}}\right)=% \left(\hat{F}{{\Psi}_{1}},{{\Psi}_{2}}\right)\quad\forall{{\Psi}_{1}},{{\Psi}_% {2}}\in H}} 
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MathML (experimentell; keine Bilder) rendering

MathML (1.3 KB / 314 B) :

(Ψ1,F^Ψ2)=(F^Ψ1,Ψ2)∀Ψ1,Ψ2∈H
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Calculated based on the variables occurring on the entire Operatoren im Hilbertraum page

Identifiers

  • Ψ1
  • F^
  • Ψ2
  • F^
  • Ψ1
  • Ψ2
  • Ψ1
  • Ψ2
  • H

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