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Display information for equation id:math.2032.31 on revision:2032

* Page found: Vektorfelder als dynamische Systeme (eq math.2032.31)

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Hash: 62db9a608432f002758562303cd99ba4

TeX (original user input): 

\det (A-\lambda 1)=0\Rightarrow \left| \left( \begin{matrix}
   -\lambda  & \frac{1}{m{{l}^{2}}}  \\
   -mgl & -\lambda   \\
\end{matrix} \right) \right|=0={{\lambda }^{2}}+\frac{g}{l}

TeX (checked): 

\det(A-\lambda 1)=0\Rightarrow \left|\left({\begin{matrix}-\lambda &{\frac {1}{m{{l}^{2}}}}\\-mgl&-\lambda \\\end{matrix}}\right)\right|=0={{\lambda }^{2}}+{\frac {g}{l}}

LaTeXML (experimentell; verwendet MathML) rendering

MathML (11.274 KB / 1.771 KB) :

det ⁡ ( A - λ ⁢ 1 ) = 0 ⇒ | ( - λ 1 m ⁢ l 2 - m ⁢ g ⁢ l - λ ) | = 0 = λ 2 + g l 𝐴 𝜆 1 0 ⇒ 𝜆 1 𝑚 superscript 𝑙 2 𝑚 𝑔 𝑙 𝜆 0 superscript 𝜆 2 𝑔 𝑙 {\displaystyle{\displaystyle\det(A-\lambda 1)=0\Rightarrow\left|\left(\begin{% matrix}-\lambda&\frac{1}{m{{l}^{2}}}\\ -mgl&-\lambda\\ \end{matrix}\right)\right|=0={{\lambda}^{2}}+\frac{g}{l}}}

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MathML (experimentell; keine Bilder) rendering

MathML (1.343 KB / 403 B) :

det⁡(A−λ1)=0⇒|(−λ1ml2−mgl−λ)|=0=λ2+gl

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