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Display information for equation id:math.2605.15 on revision:2605

* Page found: Prüfungsfragen:Quantenmechanik (eq math.2605.15)

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Hash: bf12e4d449618a92382118c0b903e58a

TeX (original user input):

\alpha\rangle=e^{-{|\alpha|^2\over2}}\sum_{n=0}^{\infty}{\alpha^n\over\sqrt{n!}}|n\rangle

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MathML (7.044 KB / 1.341 KB) :

α = e - | α | 2 2 n = 0 α n n ! | n fragments fragments α superscript 𝑒 superscript 𝛼 2 2 superscript subscript 𝑛 0 superscript 𝛼 𝑛 𝑛 | n {\displaystyle{\displaystyle\alpha\rangle=e^{-{|\alpha|^{2}\over 2}}\sum_{n=0}% ^{\infty}{\alpha^{n}\over\sqrt{n!}}|n\rangle}}

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MathML (experimentell; keine Bilder) rendering

MathML (1.005 KB / 331 B) :

α=e|α|22n=0αnn!|n

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