F μ ν = ( 0 − E 1 − E 2 − E 3 E 1 0 − B 3 B 2 E 2 B 3 0 − B 1 E 3 − B 2 B 1 0 ) {\displaystyle {{F}^{\mu \nu }}=\left({\begin{matrix}0&-{{E}_{1}}&-{{E}_{2}}&-{{E}_{3}}\\{{E}_{1}}&0&-{{B}_{3}}&{{B}_{2}}\\{{E}_{2}}&{{B}_{3}}&0&-{{B}_{1}}\\{{E}_{3}}&-{{B}_{2}}&{{B}_{1}}&0\\\end{matrix}}\right)} T α β = 1 4 π ( F α σ F σ β − 1 4 η α β F μ ν F μ ν ) {\displaystyle {{T}^{\alpha \beta }}={\frac {1}{4\pi }}\left({{F}^{\alpha }}_{\sigma }{{F}^{\sigma \beta }}-{\frac {1}{4}}{{\eta }^{\alpha \beta }}{{F}_{\mu \nu }}{{F}^{\mu \nu }}\right)}