Liouville-von-Neumann-Gleichung: Unterschied zwischen den Versionen

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Zeile 22: Zeile 22:
Ket:
Ket:
<math>\begin{align}
<math>\begin{align}
   & \left| \mathfrak{i}{{\partial }_{t}}\Psi \left( t \right) \right\rangle =\left| \hat{H}\Psi \left( t \right) \right\rangle  \\  
   & \left| \mathfrak{i}{{\partial }_{t}}\Psi \left( t \right) \right\rangle =\left| \hat{H}\Psi \left( t \right) \right\rangle  \\
  & \mathfrak{i}{{\partial }_{t}}\left| \Psi \left( t \right) \right\rangle =\hat{H}\left| \Psi \left( t \right) \right\rangle \Rightarrow {{\partial }_{t}}\left| \Psi \left( t \right) \right\rangle =-\mathfrak{i}\hat{H}\left| \Psi \left( t \right) \right\rangle  \\  
  & \mathfrak{i}{{\partial }_{t}}\left| \Psi \left( t \right) \right\rangle =\hat{H}\left| \Psi \left( t \right) \right\rangle \Rightarrow {{\partial }_{t}}\left| \Psi \left( t \right) \right\rangle =-\mathfrak{i}\hat{H}\left| \Psi \left( t \right) \right\rangle  \\
\end{align}</math>
\end{align}</math>


Zeile 30: Zeile 30:
<math>\begin{align}
<math>\begin{align}
   & \left\langle  \mathfrak{i}{{\partial }_{t}}\Psi \left( t \right) \right|=\left\langle  \hat{H}\Psi \left( t \right) \right| \\  
   & \left\langle  \mathfrak{i}{{\partial }_{t}}\Psi \left( t \right) \right|=\left\langle  \hat{H}\Psi \left( t \right) \right| \\  
  & \text{-}\mathfrak{i}{{\partial }_{t}}\left\langle  \Psi \left( t \right) \right|=\hat{H}\left\langle  \Psi \left( t \right) \right|,\,\hat{H}={{{\hat{H}}}^{+}}\Rightarrow {{\partial }_{t}}\left\langle  \Psi \left( t \right) \right|=\mathfrak{i}\hat{H}\left\langle  \Psi \left( t \right) \right| \\  
  & \text{-}\mathfrak{i}{{\partial }_{t}}\left\langle  \Psi \left( t \right) \right|=\left\langle  \Psi \left( t \right) \right|\hat{H},\,\left( \hat{H}={{{\hat{H}}}^{+}} \right)\Rightarrow {{\partial }_{t}}\left\langle  \Psi \left( t \right) \right|=\mathfrak{i}\left\langle  \Psi \left( t \right) \right|\hat{H} \\  
\end{align}</math>
\end{align}</math>




[[Dichtematrix]]
[[Dichtematrix]]


<math>\hat{\rho }=\left| \Psi \left( t \right) \right\rangle \left\langle  \Psi \left( t \right) \right|</math>
<math>\rho =\left| \Psi \left( t \right) \right\rangle \left\langle  \Psi \left( t \right) \right|</math>
 
einsetzen:
 
<math>\begin{align}
  & \dot{\rho }={{\partial }_{t}}\left( \left| \Psi \left( t \right) \right\rangle \left\langle  \Psi \left( t \right) \right| \right) \\
& =\left( {{\partial }_{t}}\left| \Psi \left( t \right) \right\rangle \right)\left\langle  \Psi \left( t \right) \right|+\left| \Psi \left( t \right) \right\rangle \left( {{\partial }_{t}}\left\langle  \Psi \left( t \right) \right| \right) \\
& =-\mathfrak{i}\hat{H}\left| \Psi \left( t \right) \right\rangle \left\langle  \Psi \left( t \right) \right|+\left| \Psi \left( t \right) \right\rangle \left\langle  \Psi \left( t \right) \right|\mathfrak{i}\hat{H} \\
& =-\mathfrak{i}\left( \hat{H}\rho -\rho \hat{H} \right)=-\mathfrak{i}\left[ \hat{H},\rho  \right]=\mathfrak{i}\left[ \rho ,\hat{H} \right] 
\end{align}</math>


== Einzelnachweise ==
== Einzelnachweise ==
<references />
<references />
[http://de.wikipedia.org/wiki/Von-Neumann-Gleichung Wikipedia-Eintrag]
[http://de.wikipedia.org/wiki/Von-Neumann-Gleichung Wikipedia-Eintrag]

Version vom 7. September 2009, 00:23 Uhr

mit

Dichteoperator
H Hamiltonoperator
Kommutator

[1]

Herleitung

Schrödingergleichung


Dirac Notation

Ket:

Bra:


Dichtematrix

einsetzen:

Einzelnachweise

  1. Schöll, QM 2.5 Teil 1 Seite 77,

Wikipedia-Eintrag