Liouville-von-Neumann-Gleichung: Unterschied zwischen den Versionen

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<math>\begin{align}
<math>\begin{align}
   & \left\langle  \mathfrak{i}{{\partial }_{t}}\Psi \left( t \right) \right|=\left\langle  \hat{H}\Psi \left( t \right) \right| \\  
   & \left\langle  \mathfrak{i}{{\partial }_{t}}\Psi \left( t \right) \right|=\left\langle  \hat{H}\Psi \left( t \right) \right| \\
  & \text{-}\mathfrak{i}{{\partial }_{t}}\left\langle  \Psi \left( t \right) \right|=\left\langle  \Psi \left( t \right) \right|\hat{H},\,\left( \hat{H}={{{\hat{H}}}^{+}} \right)\Rightarrow {{\partial }_{t}}\left\langle  \Psi \left( t \right) \right|=\mathfrak{i}\left\langle  \Psi \left( t \right) \right|\hat{H} \\  
  & \text{-}\mathfrak{i}{{\partial }_{t}}\left\langle  \Psi \left( t \right) \right|=\left\langle  \Psi \left( t \right) \right|\hat{H},\,\left( \hat{H}={{{\hat{H}}}^{+}} \right)\Rightarrow {{\partial }_{t}}\left\langle  \Psi \left( t \right) \right|=\mathfrak{i}\left\langle  \Psi \left( t \right) \right|\hat{H} \\
\end{align}</math>
\end{align}</math>


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<math>\begin{align}
<math>\begin{align}
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  & =\left( {{\partial }_{t}}\left| \Psi \left( t \right) \right\rangle  \right)\left\langle  \Psi \left( t \right) \right|+\left| \Psi \left( t \right) \right\rangle \left( {{\partial }_{t}}\left\langle  \Psi \left( t \right) \right| \right) \\  
  & =\left( {{\partial }_{t}}\left| \Psi \left( t \right) \right\rangle  \right)\left\langle  \Psi \left( t \right) \right|+\left| \Psi \left( t \right) \right\rangle \left( {{\partial }_{t}}\left\langle  \Psi \left( t \right) \right| \right) \\  
  & =-\mathfrak{i}\hat{H}\left| \Psi \left( t \right) \right\rangle \left\langle  \Psi \left( t \right) \right|+\left| \Psi \left( t \right) \right\rangle \left\langle  \Psi \left( t \right) \right|\mathfrak{i}\hat{H} \\  
  & =-\mathfrak{i}\hat{H}\left| \Psi \left( t \right) \right\rangle \left\langle  \Psi \left( t \right) \right|+\left| \Psi \left( t \right) \right\rangle \left\langle  \Psi \left( t \right) \right|\mathfrak{i}\hat{H} \\  
  & =-\mathfrak{i}\left( \hat{H}\rho -\rho \hat{H} \right)=-\mathfrak{i}\left[ \hat{H},\rho  \right]=\mathfrak{i}\left[ \rho ,\hat{H} \right]   
  & =-\mathfrak{i}\left( \hat{H}\rho -\rho \hat{H} \right)\equiv -\mathfrak{i}\left[ \hat{H},\rho  \right]=\mathfrak{i}\left[ \rho ,\hat{H} \right]   
\end{align}</math>
\end{align}</math>



Version vom 7. September 2009, 00:24 Uhr

mit

Dichteoperator
H Hamiltonoperator
Kommutator

[1]

Herleitung

Schrödingergleichung


Dirac Notation

Ket:

Bra:


Dichtematrix

einsetzen:


Einzelnachweise

  1. Schöll, QM 2.5 Teil 1 Seite 77,

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