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Display information for equation id:math.2431.18 on revision:2431

* Page found: Entropie von Gleichgewichtszuständen (eq math.2431.18)

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Hash: 4a4ad86f49a9b7d45ef5b37ca484c8b2

TeX (original user input):

\begin{align}

& dS\left( \left\langle {{M}^{n}} \right\rangle  \right)=k\beta dU \\

& \frac{\partial S\left( \left\langle {{M}^{n}} \right\rangle  \right)}{\partial U}=k\beta =:\frac{1}{T} \\

\end{align}

TeX (checked):

{\begin{aligned}&dS\left(\left\langle {{M}^{n}}\right\rangle \right)=k\beta dU\\&{\frac {\partial S\left(\left\langle {{M}^{n}}\right\rangle \right)}{\partial U}}=k\beta =:{\frac {1}{T}}\\\end{aligned}}

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MathML (experimentell; keine Bilder) rendering

MathML (1.594 KB / 388 B) :

dS(Mn)=kβdUS(Mn)U=kβ=:1T

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Calculated based on the variables occurring on the entire Entropie von Gleichgewichtszuständen page

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