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Display information for equation id:math.1914.10 on revision:1914

* Page found: Theorem von Noether (eq math.1914.10)

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TeX (original user input): 

\frac{d}{ds}L(\bar{q}(s,t),\dot{\bar{q}}(s,t))=\sum\limits_{i=1}^{f}{\left( \frac{\partial L}{\partial {{q}_{i}}}\left( \frac{d{{q}_{i}}}{ds} \right)+\frac{\partial L}{\partial {{{\dot{q}}}_{i}}}{{\left( \frac{d{{{\dot{q}}}_{i}}}{ds} \right)}_{{}}} \right)=}0

TeX (checked): 

{\frac {d}{ds}}L({\bar {q}}(s,t),{\dot {\bar {q}}}(s,t))=\sum \limits _{i=1}^{f}{\left({\frac {\partial L}{\partial {{q}_{i}}}}\left({\frac {d{{q}_{i}}}{ds}}\right)+{\frac {\partial L}{\partial {{\dot {q}}_{i}}}}{{\left({\frac {d{{\dot {q}}_{i}}}{ds}}\right)}_{}}\right)=}0

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d d ⁢ s ⁢ L ⁢ ( q ¯ ⁢ ( s , t ) , q ¯ ˙ ⁢ ( s , t ) ) = ∑ i = 1 f ( ∂ ⁡ L ∂ ⁡ q i ⁢ ( d ⁢ q i d ⁢ s ) + ∂ ⁡ L ∂ ⁡ q ˙ i ⁢ ( d ⁢ q ˙ i d ⁢ s ) ) = 0 𝑑 𝑑 𝑠 𝐿 ¯ 𝑞 𝑠 𝑡 ˙ ¯ 𝑞 𝑠 𝑡 superscript subscript 𝑖 1 𝑓 𝐿 subscript 𝑞 𝑖 𝑑 subscript 𝑞 𝑖 𝑑 𝑠 𝐿 subscript ˙ 𝑞 𝑖 𝑑 subscript ˙ 𝑞 𝑖 𝑑 𝑠 0 {\displaystyle{\displaystyle\frac{d}{ds}L(\bar{q}(s,t),\dot{\bar{q}}(s,t))=% \sum\limits_{i=1}^{f}{\left(\frac{\partial L}{\partial{{q}_{i}}}\left(\frac{d{% {q}_{i}}}{ds}\right)+\frac{\partial L}{\partial{{{\dot{q}}}_{i}}}{{\left(\frac% {d{{{\dot{q}}}_{i}}}{ds}\right)}}\right)=}0}}

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MathML (2.961 KB / 430 B) :

ddsL(q¯(s,t),q¯˙(s,t))=∑i=1f(∂L∂qi(dqids)+∂L∂q˙i(dq˙ids))=0

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  • d
  • d
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  • q¯
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  • t
  • q¯˙
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  • t
  • i
  • f
  • L
  • qi
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  • qi
  • d
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  • L
  • q˙i
  • d
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  • d
  • s

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