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Display information for equation id:math.1914.4 on revision:1914

* Page found: Theorem von Noether (eq math.1914.4)

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TeX (original user input): 

I(\bar{q},\dot{\bar{q}})=\sum\limits_{i=1}^{f}{\frac{\partial L}{\partial {{{\dot{q}}}_{i}}}{{\left( \frac{d}{ds}{{h}^{s}}({{q}_{i}}) \right)}_{s=0}}}

TeX (checked): 

I({\bar {q}},{\dot {\bar {q}}})=\sum \limits _{i=1}^{f}{{\frac {\partial L}{\partial {{\dot {q}}_{i}}}}{{\left({\frac {d}{ds}}{{h}^{s}}({{q}_{i}})\right)}_{s=0}}}

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MathML (11.889 KB / 1.821 KB) :

I ⁢ ( q ¯ , q ¯ ˙ ) = ∑ i = 1 f ∂ ⁡ L ∂ ⁡ q ˙ i ⁢ ( d d ⁢ s ⁢ h s ⁢ ( q i ) ) s = 0 𝐼 ¯ 𝑞 ˙ ¯ 𝑞 superscript subscript 𝑖 1 𝑓 𝐿 subscript ˙ 𝑞 𝑖 subscript 𝑑 𝑑 𝑠 superscript ℎ 𝑠 subscript 𝑞 𝑖 𝑠 0 {\displaystyle{\displaystyle I(\bar{q},\dot{\bar{q}})=\sum\limits_{i=1}^{f}{% \frac{\partial L}{\partial{{{\dot{q}}}_{i}}}{{\left(\frac{d}{ds}{{h}^{s}}({{q}% _{i}})\right)}_{s=0}}}}}

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MathML (experimentell; keine Bilder) rendering

MathML (1.817 KB / 408 B) :

I(q¯,q¯˙)=∑i=1f∂L∂q˙i(ddshs(qi))s=0

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  • q¯
  • q¯˙
  • i
  • f
  • L
  • q˙i
  • d
  • d
  • s
  • h
  • s
  • qi
  • s

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