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Display information for equation id:math.1914.7 on revision:1914

* Page found: Theorem von Noether (eq math.1914.7)

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\frac{d}{dt}\frac{\partial L(\bar{q}(s,t),\dot{\bar{q}}(s,t))}{\partial {{{\dot{q}}}_{i}}}=\frac{\partial L(\bar{q}(s,t),\dot{\bar{q}}(s,t))}{\partial {{q}_{i}}}

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d d ⁢ t ⁢ ∂ ⁡ L ⁢ ( q ¯ ⁢ ( s , t ) , q ¯ ˙ ⁢ ( s , t ) ) ∂ ⁡ q ˙ i = ∂ ⁡ L ⁢ ( q ¯ ⁢ ( s , t ) , q ¯ ˙ ⁢ ( s , t ) ) ∂ ⁡ q i 𝑑 𝑑 𝑡 𝐿 ¯ 𝑞 𝑠 𝑡 ˙ ¯ 𝑞 𝑠 𝑡 subscript ˙ 𝑞 𝑖 𝐿 ¯ 𝑞 𝑠 𝑡 ˙ ¯ 𝑞 𝑠 𝑡 subscript 𝑞 𝑖 {\displaystyle{\displaystyle\frac{d}{dt}\frac{\partial L(\bar{q}(s,t),\dot{% \bar{q}}(s,t))}{\partial{{{\dot{q}}}_{i}}}=\frac{\partial L(\bar{q}(s,t),\dot{% \bar{q}}(s,t))}{\partial{{q}_{i}}}}}

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ddt∂L(q¯(s,t),q¯˙(s,t))∂q˙i=∂L(q¯(s,t),q¯˙(s,t))∂qi

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