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Display information for equation id:math.1922.8 on revision:1922

* Page found: Das Zweikörperproblem (eq math.1922.8)

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Hash: 3872a913508cfdd542fee3059b8418cc

TeX (original user input):

E=\frac{1}{2}{{m}_{1}}{{\bar{v}}_{1}}^{2}+\frac{1}{2}{{m}_{2}}{{\bar{v}}_{2}}^{2}+V\left( \left| {{{\bar{r}}}_{1}}-{{{\bar{r}}}_{2}} \right| \right)=const

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MathML (12.775 KB / 1.803 KB) :

E = 1 2 m 1 v ¯ 1 2 + 1 2 m 2 v ¯ 2 2 + V ( | r ¯ 1 - r ¯ 2 | ) = c o n s t 𝐸 1 2 subscript 𝑚 1 superscript subscript ¯ 𝑣 1 2 1 2 subscript 𝑚 2 superscript subscript ¯ 𝑣 2 2 𝑉 subscript ¯ 𝑟 1 subscript ¯ 𝑟 2 𝑐 𝑜 𝑛 𝑠 𝑡 {\displaystyle{\displaystyle E=\frac{1}{2}{{m}_{1}}{{\bar{v}}_{1}}^{2}+\frac{1% }{2}{{m}_{2}}{{\bar{v}}_{2}}^{2}+V\left(\left|{{{\bar{r}}}_{1}}-{{{\bar{r}}}_{% 2}}\right|\right)=const}}

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MathML (experimentell; keine Bilder) rendering

MathML (1.709 KB / 341 B) :

E=12m1v¯12+12m2v¯22+V(|r¯1r¯2|)=const

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