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Display information for equation id:math.2107.3 on revision:2107

* Page found: TCP- Invarianz (eq math.2107.3)

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TeX (original user input): 

\begin{align}
& T:\left\{ {{\nabla }_{r}}\times \bar{E}=0 \right\}\to \left\{ {{\nabla }_{r}}\times \bar{E}=0 \right\} \\
& T:\left\{ {{\varepsilon }_{0}}{{\nabla }_{r}}\cdot \bar{E}=\rho  \right\}\to \left\{ {{\varepsilon }_{0}}{{\nabla }_{r}}\cdot \bar{E}=\rho  \right\} \\
& T:\left\{ {{\nabla }_{r}}\cdot \bar{B}=0 \right\}\to \left\{ -{{\nabla }_{r}}\cdot \bar{B}=0 \right\}\Leftrightarrow \left\{ {{\nabla }_{r}}\cdot \bar{B}=0 \right\} \\
& T:\left\{ \nabla \times \bar{B}={{\mu }_{0}}\bar{j} \right\}\to \left\{ -\nabla \times \bar{B}=-{{\mu }_{0}}\bar{j} \right\} \\
&  \\
\end{align}

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MathML (32.138 KB / 3.364 KB) :

T : { ∇ r × E ¯ = 0 } → { ∇ r × E ¯ = 0 } T : { ε 0 ∇ r ⋅ E ¯ = ρ } → { ε 0 ∇ r ⋅ E ¯ = ρ } T : { ∇ r ⋅ B ¯ = 0 } → { - ∇ r ⋅ B ¯ = 0 } ⇔ { ∇ r ⋅ B ¯ = 0 } T : { ∇ × B ¯ = μ 0 j ¯ } → { - ∇ × B ¯ = - μ 0 j ¯ } missing-subexpression fragments T : fragments { subscript ∇ 𝑟 ¯ 𝐸 0 } → fragments { subscript ∇ 𝑟 ¯ 𝐸 0 } missing-subexpression fragments T : fragments { subscript 𝜀 0 subscript ∇ 𝑟 ⋅ ¯ 𝐸 ρ } → fragments { subscript 𝜀 0 subscript ∇ 𝑟 ⋅ ¯ 𝐸 ρ } missing-subexpression fragments T : fragments { subscript ∇ 𝑟 ⋅ ¯ 𝐵 0 } → fragments { subscript ∇ 𝑟 ⋅ ¯ 𝐵 0 } ⇔ fragments { subscript ∇ 𝑟 ⋅ ¯ 𝐵 0 } missing-subexpression fragments T : fragments { ∇ ¯ 𝐵 subscript 𝜇 0 ¯ 𝑗 } → fragments { ∇ ¯ 𝐵 subscript 𝜇 0 ¯ 𝑗 } missing-subexpression missing-subexpression {\displaystyle{\displaystyle\begin{aligned} &\displaystyle T:\left\{{{\nabla}_% {r}}\times\bar{E}=0\right\}\to\left\{{{\nabla}_{r}}\times\bar{E}=0\right\}\\ &\displaystyle T:\left\{{{\varepsilon}_{0}}{{\nabla}_{r}}\cdot\bar{E}=\rho% \right\}\to\left\{{{\varepsilon}_{0}}{{\nabla}_{r}}\cdot\bar{E}=\rho\right\}\\ &\displaystyle T:\left\{{{\nabla}_{r}}\cdot\bar{B}=0\right\}\to\left\{-{{% \nabla}_{r}}\cdot\bar{B}=0\right\}\Leftrightarrow\left\{{{\nabla}_{r}}\cdot% \bar{B}=0\right\}\\ &\displaystyle T:\left\{\nabla\times\bar{B}={{\mu}_{0}}\bar{j}\right\}\to\left% \{-\nabla\times\bar{B}=-{{\mu}_{0}}\bar{j}\right\}\\ &\\ \end{aligned}}}

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T:{∇r×E¯=0}→{∇r×E¯=0}T:{ε0∇r⋅E¯=ρ}→{ε0∇r⋅E¯=ρ}T:{∇r⋅B¯=0}→{−∇r⋅B¯=0}⇔{∇r⋅B¯=0}T:{∇×B¯=μ0j¯}→{−∇×B¯=−μ0j¯}

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