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Display information for equation id:math.2284.36 on revision:2284

* Page found: Beispiel des Großkanonischen Ensenbles (eq math.2284.36)

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Occurrences on the following pages:

Hash: 272f6768b58249f636854fb29f890b63

TeX (original user input):

\begin{align}
  & {{\left( \frac{\partial {{S}_{1}}}{\partial {{E}_{1}}} \right)}_{{{V}_{1}},{{{\bar{N}}}_{1}}}}={{\left( \frac{\partial {{S}_{2}}}{\partial {{E}_{2}}} \right)}_{{{V}_{2}},{{{\bar{N}}}_{2}}}} \\
 & {{\left( \frac{\partial {{S}_{1}}}{\partial {{{\bar{N}}}_{1}}} \right)}_{{{V}_{1}},{{E}_{1}}}}={{\left( \frac{\partial {{S}_{2}}}{\partial {{{\bar{N}}}_{2}}} \right)}_{{{V}_{2}},{{E}_{2}}}} \\
 & {{\left( \frac{\partial {{S}_{1}}}{\partial {{V}_{1}}} \right)}_{{{E}_{1}},{{{\bar{N}}}_{1}}}}={{\left( \frac{\partial {{S}_{2}}}{\partial {{V}_{2}}} \right)}_{{{E}_{2}},{{{\bar{N}}}_{2}}}} 
\end{align}

TeX (checked):

{\begin{aligned}&{{\left({\frac {\partial {{S}_{1}}}{\partial {{E}_{1}}}}\right)}_{{{V}_{1}},{{\bar {N}}_{1}}}}={{\left({\frac {\partial {{S}_{2}}}{\partial {{E}_{2}}}}\right)}_{{{V}_{2}},{{\bar {N}}_{2}}}}\\&{{\left({\frac {\partial {{S}_{1}}}{\partial {{\bar {N}}_{1}}}}\right)}_{{{V}_{1}},{{E}_{1}}}}={{\left({\frac {\partial {{S}_{2}}}{\partial {{\bar {N}}_{2}}}}\right)}_{{{V}_{2}},{{E}_{2}}}}\\&{{\left({\frac {\partial {{S}_{1}}}{\partial {{V}_{1}}}}\right)}_{{{E}_{1}},{{\bar {N}}_{1}}}}={{\left({\frac {\partial {{S}_{2}}}{\partial {{V}_{2}}}}\right)}_{{{E}_{2}},{{\bar {N}}_{2}}}}\end{aligned}}

LaTeXML (experimentell; verwendet MathML) rendering

MathML (39.117 KB / 3.645 KB) :

( S 1 E 1 ) V 1 , N ¯ 1 = ( S 2 E 2 ) V 2 , N ¯ 2 ( S 1 N ¯ 1 ) V 1 , E 1 = ( S 2 N ¯ 2 ) V 2 , E 2 ( S 1 V 1 ) E 1 , N ¯ 1 = ( S 2 V 2 ) E 2 , N ¯ 2 missing-subexpression subscript subscript 𝑆 1 subscript 𝐸 1 subscript 𝑉 1 subscript ¯ 𝑁 1 subscript subscript 𝑆 2 subscript 𝐸 2 subscript 𝑉 2 subscript ¯ 𝑁 2 missing-subexpression subscript subscript 𝑆 1 subscript ¯ 𝑁 1 subscript 𝑉 1 subscript 𝐸 1 subscript subscript 𝑆 2 subscript ¯ 𝑁 2 subscript 𝑉 2 subscript 𝐸 2 missing-subexpression subscript subscript 𝑆 1 subscript 𝑉 1 subscript 𝐸 1 subscript ¯ 𝑁 1 subscript subscript 𝑆 2 subscript 𝑉 2 subscript 𝐸 2 subscript ¯ 𝑁 2 {\displaystyle{\displaystyle\begin{aligned} &\displaystyle{{\left(\frac{% \partial{{S}_{1}}}{\partial{{E}_{1}}}\right)}_{{{V}_{1}},{{{\bar{N}}}_{1}}}}={% {\left(\frac{\partial{{S}_{2}}}{\partial{{E}_{2}}}\right)}_{{{V}_{2}},{{{\bar{% N}}}_{2}}}}\\ &\displaystyle{{\left(\frac{\partial{{S}_{1}}}{\partial{{{\bar{N}}}_{1}}}% \right)}_{{{V}_{1}},{{E}_{1}}}}={{\left(\frac{\partial{{S}_{2}}}{\partial{{{% \bar{N}}}_{2}}}\right)}_{{{V}_{2}},{{E}_{2}}}}\\ &\displaystyle{{\left(\frac{\partial{{S}_{1}}}{\partial{{V}_{1}}}\right)}_{{{E% }_{1}},{{{\bar{N}}}_{1}}}}={{\left(\frac{\partial{{S}_{2}}}{\partial{{V}_{2}}}% \right)}_{{{E}_{2}},{{{\bar{N}}}_{2}}}}\end{aligned}}}

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MathML (experimentell; keine Bilder) rendering

MathML (5.329 KB / 445 B) :

(S1E1)V1,N¯1=(S2E2)V2,N¯2(S1N¯1)V1,E1=(S2N¯2)V2,E2(S1V1)E1,N¯1=(S2V2)E2,N¯2

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Calculated based on the variables occurring on the entire Beispiel des Großkanonischen Ensenbles page

Identifiers

  • S1
  • E1
  • V1
  • N¯1
  • S2
  • E2
  • V2
  • N¯2
  • S1
  • N¯1
  • V1
  • E1
  • S2
  • N¯2
  • V2
  • E2
  • S1
  • V1
  • E1
  • N¯1
  • S2
  • V2
  • E2
  • N¯2

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