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Display information for equation id:math.2492.49 on revision:2492

* Page found: Gleichgewichtsbedingungen (eq math.2492.49)

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Hash: 2cb87526bdf8ad7610a4d008d4f9adce

TeX (original user input): 

dF=d\left( U-TS \right)=dU-TdS=!=\delta W=\left( p\acute{\ }\acute{\ }-p\acute{\ }+\frac{2}{r}\sigma  \right)dV\acute{\ }=!=0

LaTeXML (experimentell; verwendet MathML) rendering

MathML (8.425 KB / 1.451 KB) :

d F = d ( U - T S ) = d U - T d S = ! = δ W = ( p ´ ´ - p ´ + 2 r σ ) d V ´ = ! = 0 fragments d F d fragments ( U T S ) d U T d S δ W fragments ( p ´ absent ´ absent p ´ absent 2 𝑟 σ ) d V ´ absent 0 {\displaystyle{\displaystyle dF=d\left(U-TS\right)=dU-TdS=!=\delta W=\left(p% \acute{\ }\acute{\ }-p\acute{\ }+\frac{2}{r}\sigma\right)dV\acute{\ }=!=0}} 
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MathML (experimentell; keine Bilder) rendering

MathML (1.465 KB / 363 B) :

dF=d(U−TS)=dU−TdS=!=δW=(p´´−p´+2rσ)dV´=!=0
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