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Display information for equation id:math.2731.4 on revision:2731

* Page found: Prüfungsfragen:Elektrodynamik (eq math.2731.4)

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Hash: 4b9eadaeceb92ad137843a3c980d4495

TeX (original user input):

\hbar \omega= E = \frac{p^2}{2m} = \frac{\hbar^2 k^2}{2m}

TeX (checked):

\hbar \omega =E={\frac {p^{2}}{2m}}={\frac {\hbar ^{2}k^{2}}{2m}}

LaTeXML (experimentell; verwendet MathML) rendering

MathML (6.104 KB / 1.098 KB) :

ω = E = p 2 2 m = 2 k 2 2 m Planck-constant-over-2-pi 𝜔 𝐸 superscript 𝑝 2 2 𝑚 superscript Planck-constant-over-2-pi 2 superscript 𝑘 2 2 𝑚 {\displaystyle{\displaystyle\hbar\omega=E=\frac{p^{2}}{2m}=\frac{\hbar^{2}k^{2% }}{2m}}}

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MathML (experimentell; keine Bilder) rendering

MathML (911 B / 257 B) :

ω=E=p22m=2k22m

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  • ω
  • E
  • p
  • m
  • k
  • m

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