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Display information for equation id:math.2524.19 on revision:2524

* Page found: Klassisch- mechanische Gleichgewichtsverteilungen (eq math.2524.19)

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Hash: 2daa165afeadfb2782b96849660c4cca

TeX (original user input):

\begin{align}

& \frac{\partial \rho \left( \xi ,t \right)}{\partial t}+div\left( \rho \dot{\xi } \right)=\frac{\partial \rho \left( \xi ,t \right)}{\partial t}+\sum\limits_{k=1}^{3N}{{}}\left( \frac{\partial \rho \left( \xi ,t \right)}{\partial {{q}_{k}}}{{{\dot{q}}}_{k}}+\frac{\partial \rho \left( \xi ,t \right)}{\partial {{p}_{k}}}{{{\dot{p}}}_{k}} \right)+\rho div\dot{\xi } \\

& \rho div\dot{\xi }=0 \\

& \Rightarrow \frac{\partial \rho \left( \xi ,t \right)}{\partial t}+div\left( \rho \dot{\xi } \right)=\frac{\partial \rho \left( \xi ,t \right)}{\partial t}+\sum\limits_{k=1}^{3N}{{}}\left( \frac{\partial \rho \left( \xi ,t \right)}{\partial {{q}_{k}}}{{{\dot{q}}}_{k}}+\frac{\partial \rho \left( \xi ,t \right)}{\partial {{p}_{k}}}{{{\dot{p}}}_{k}} \right)=\frac{d\rho \left( \xi ,t \right)}{dt}=0 \\

\end{align}

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ρ(ξ,t)t+div(ρξ˙)=ρ(ξ,t)t+k=13N(ρ(ξ,t)qkq˙k+ρ(ξ,t)pkp˙k)+ρdivξ˙ρdivξ˙=0ρ(ξ,t)t+div(ρξ˙)=ρ(ξ,t)t+k=13N(ρ(ξ,t)qkq˙k+ρ(ξ,t)pkp˙k)=dρ(ξ,t)dt=0

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